doulbe het sunglow x double het sunglow (boas)

[lee-travis]

i have a question that has been racking my brains for quite a while. I if was to breed 2 double het sunglow boas together (SsAa x SsAa) would would i get out of a clutch of 16?

i understand that the albino size of things, in that if ssaa for example was one of the offspring would this just be an albino?

what i dont understand is how the hypo (salmon) trait works. if one of the offspring is SSAA does that mean they are salmon or SsAA does that mean that this individual is het salmon?

are the below prediction right:

SA Sa sA sa

SA SSAA SSAaSsAA SsAa

Sa SSAa SSaa SsAa Ssaa

sA SsAA SsAa ssAA ssAa

sa SsAa Ssaa ssAa ssaa

are these prediction right and can you explain in detail what each one of the offspring is?

many thanks

[Ssthisto]

If you have a litter of sixteen you could get anything from all normals to all sunglows. The chance of "1 in 16" is per OFFSPRING not per litter.

Hypo is dominant, so an animal with one copy looks the same as an animal with two copies. SS looks the same as Ss - and only an ss is normal.

Anything that is SS or Ss will be visually hypo. Anything that is ss is visually not hypo and does not carry hypo.

Anything that is aa is visually albino. Anything that is AA or Aa is visually non-albino and would be considered "possible hets".

Therefore, your punnett square shows:

SSAA - Homozygous hypo, non-albino (1:16 chance per offspring)
SSAa - Homozygous hypo, non-albino but het for albino (1:8 chance per offspring)
SSaa - Homozygous hypo, albino AKA Sunglow (1:16 chance per offspring)
SsAA - Heterozygous hypo, non-albino (1:8 chance per offspring)
SsAa - Heterozygous hypo, non-albino but het for albino (1:4 chance per offspring)
Ssaa - Heterozygous hypo, albino AKA Sunglow (1:8 chance per offspring)
ssAA - Non-hypo, non-albino (1:16 chance per offspring)
ssAa - Non-hypo, non-albino but het for albino (1:8 chance per offspring)
ssaa - Non-hypo, albino (1:16 chance per offspring).

All your non-albinos would be CALLED "66% chance het Albino" as there's a two in three chance they inherited the albino gene from one parent or the other.

The homozygous hypos might be distinguishable from the heterozygous hypos but there's no guarantee.

[lee-travis]

cheers for that, thats what i had as a final answer aswell (just wanted to make sure i wasnt going wrong anywhere) but i think i was getting a little confused over 1:16 chance per animal rather than per litter, but i get it now so thanks.

[Ssthisto]

Yeah, it'd be nice if you were guaranteed those perfect ratios, but what it really is would be more like flipping two pennies and two tenpence - what you need is at least one heads on the tenpence and BOTH pennies to be heads in order to get a Sunglow - but each flip of the coin is independent to any other flip.

[lee-travis]

yeah... so am i right in say if you had a large female that had a large little (more than the normal range) you would have a greater chance of getting sunglows from this?

cheers for the help anyway

[Ssthisto]

Yup, the more times you flip the coins, the more chances you have to get the exact flip you need... but the more chances you ALSO have to get all of the other possible results!

[ez4pro]

In an ideal world what is the potential outcome percentages for a Double het sunglow x Sunglow pairing in relation to the ubove?

Cheers

Chris

[Ssthisto]

Well, one in 4 is 25%.
One in 8 is 12.5%.
One in 16 is 6.25%.

[lee-travis]

if i have this right you should get

(SSaa "Sa" x SsAa)

Sa

SA SSAa
Sa SSaa
sA SsAa
sa Ssaa

so

potentially you would get (if im right dont quote me):

1/4= SSAa or super salmon het albino
1/4= SSaa or super sunglow (need to be proved geentically through breeding)
1/4=SsAa salmon het albino
1/4= Ssaa sunglow

Im sure ssthisto will correct me

[Ssthisto]

There's nothing saying a sunglow HAS to be homozygous hypo... so you'd be looking at SSaa or Ssaa as a sunglow.

You've still got the possibility of getting non-hypo offspring if you don't have a homozygous hypo Sunglow.