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Pastel is (DOMINANT) you can't get super form. Normal X Pastel(1C) = . 50%Normal. 50%Pastel(1C). ---- Normal X Pastel(2C) = . 100%Pastel(1C). ---- ---- Mack snow's are Co-dominant so. Snow X Snow = . 25%Normal. 50%Snow. 25%Super snow.
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Leopard gecko morph info. [1C]-1 Copy = (Heterozygous). [2C]-2 Copy = (Homozygous). Snow SPLIT Super snow = (Mack). [1C]Snow,[2C]Snow = (TUG,GEM). Tinted = (False eclipse). Hyper aberrant = (Jungle).
Last edited by gazz; 08-02-2009 at 02:13 AM.. |
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Edited to say this is my understanding if I havent explained it right peeps dont shout at me. Last edited by oakelm; 08-02-2009 at 02:45 AM.. Reason: . |
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Leopard gecko morph info. [1C]-1 Copy = (Heterozygous). [2C]-2 Copy = (Homozygous). Snow SPLIT Super snow = (Mack). [1C]Snow,[2C]Snow = (TUG,GEM). Tinted = (False eclipse). Hyper aberrant = (Jungle).
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i know that the 66% probabililty is just that, a probablility. i explained that it needs to go on to be proven that its either 100% or 0% but he wasnt having any of it. i hate it when we get into something like this and he flat out states i am wrong . i have been lying in bed running through it in my head, . GAH!
and is a super pastel not a super form of pastel where its in effect got a double dose of the same gene? or is it different for pastels to say.......yellowbellys where the super is ivory? i undertsand that statistics behind all this i just have a very bad way of expressing myself when i get in a rat with him.
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Royal python (Pastel) Pastel X Pastel = . 25%Normal. 50%Pastel 25%Super pastel. ---- ---- Pastel X Normal = . 50%Normal. 50%Pastel.
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Leopard gecko morph info. [1C]-1 Copy = (Heterozygous). [2C]-2 Copy = (Homozygous). Snow SPLIT Super snow = (Mack). [1C]Snow,[2C]Snow = (TUG,GEM). Tinted = (False eclipse). Hyper aberrant = (Jungle).
Last edited by gazz; 08-02-2009 at 05:40 PM.. |
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I was at uni, too, and I worked in the uni genetics lab for several years.
Impossible is a strong word. If there is at least one exception, the thing is not impossible. The other posters gave you the straight dope on 66% probability hets. But there is a way to get 66% hets without the probability. This to have a mutant gene which is lethal when homozygous. For example, the dominant yellow mutant in the house mouse is lethal when a mouse embryo has two copies of the mutant. The mouse dies before it is born. So the live mice from a dominant yellow X dominant yellow mating are either dominant yellow mice (which are hets) or homozygous normal mice. Over time, the proportions average out to approximately 2/3 dominant yellows and 1/3 normals. Dominant yellow is not unique. Crested in canaries and in zebra finches works the same way. There are others, too. |
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66% het in breeder terms is used to describe visual normals from a litter/clutch produced by a het x het cross.
Say you get the 4 statistically perfect offspring from two albino hets: One visual albino, two albino hets and one normal. There's no need to describe the albino as "100% homozygous" because it's kind of obvious, we can see it's albino! So we're left with three normal looking offspring. The probability of any of those three being one of the hets is 2/3 or 66%. This is different to the chances of producing het offspring from a het x het cross in the first place as this has a probablity of 50%. As a previous poster said, a lethal homozygous effectivly has the same effect as a visually distonct homozygous morph, it removes itself from the problem by being immediatly identifiable i.e. albino or dead.
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