morphs are confusing me!!!!

[paulh]

Originally Posted by gazz

Yes [1C] is the dominant term for HET.[2C] ofcourse the dominant term for HOMO.

Homozygous is the standard genetics term for a pair of genes that are the same. It does not matter whether the genes are normal genes, dominant mutant genes, codominant mutant genes or recessive mutant genes.

Heterozygous is the standard genetics term for a pair of genes that are not the same. It does not matter whether the two genes are a normal gene and a recessive mutant gene, a normal gene and a dominant mutant gene, a normal gene and a codominant mutant gene, or two different mutant genes.

On the other hand, 1 copy and 2 copies has the benefit of making the meaning a bit plainer to a newbie. So [1C] Tremper albino is a perfectly acceptable substitute for het Tremper albino.

[classix]

thanks for your help

i keep making the cardinal newbie sin of assuming HET as meaning Hidden


nowt PaulH i must admit when i saw this post i felt like my head was going to explode

Originally Posted by paulh

This is a three gene pair problem. Here's what I would use. (These symbols follow the rules of nomenclature for rats and mice, which the professional geneticists use.) I'm going to skip the carrottail and tangerine as those are line bred traits.

Male = Ms//Ms^+ a//a H^+//H^+
Female = Ms^+//Ms^+ a^+//a^+ H//H

Symbol meanings:
// = a pair of chromosomes

Ms = Mack snow
Ms^+ = normal version of the Mack snow gene

a = albino
a^+ = normal version of the albino gene

H = hypo
H^+ = normal version of the hypo gene

This editor does not do superscripts, so ^ sets off the superscript. H^+ stands for H with + as a superscript. + is the internationally recognized character for the normal allele for each mutant gene.

So the male is Ms//Ms^+ a//a H^+//H^+. He has a pair of chromosomes with a Mack snow gene in one chromosome and a normal gene in the other, a pair of chromosomes with an albino mutant gene in each one, and a pair of chromosomes with a normal gene in each one where the female has a hypo mutant gene.

The male produces two types of sperm, Ms a H^+ and Ms^+ a H^+.
The female produces one kind of egg, Ms^+ a^+ H.

Plug these into the Punnett square, and you get two types of babies. Clear as mud?

but i kept on studying it and devised a punnett square....please bare with me if i have done it completely wrong.

first i started by working out how i write it down, so after reading your line

Male = Ms//Ms^+ a//a H^+//H^+

i assumed i should split it into mack snow, mack snow normal, albino, albino, hypo normal, hypo normal.

so these are the headings at the top of my punnet square, i used the same method for a female and here is what my results say.

(again please bare with me if i have cocked it all up )

1/18 Ms^+//Ms
1/18 A^+//Ms
1/18 H//Ms

1/18 Ms^+ // Ms^+
1/18 A^+ // Ms^+
1/18 H // Ms^+

1/9 Ms^+ // a
1/9 A^+ // a
1/9 H // a

1/9 Ms^+ // H^+
1/9 A^+ // H^+
1/9 H // H^+

(my punnet square was a total of 36, so i have halved it down, so the 1/9 means 4 out of 36 )

so am i on the right lines here? or have i done too much/ too less?

[paulh]

Originally Posted by classix

... but i kept on studying it and devised a punnett square....please bare with me if i have done it completely wrong.

first i started by working out how i write it down, so after reading your line

Male = Ms//Ms^+ a//a H^+//H^+

i assumed i should split it into mack snow, mack snow normal, albino, albino, hypo normal, hypo normal.

so these are the headings at the top of my punnet square, i used the same method for a female and here is what my results say.

(again please bare with me if i have cocked it all up )

1/18 Ms^+//Ms
1/18 A^+//Ms
1/18 H//Ms

1/18 Ms^+ // Ms^+
1/18 A^+ // Ms^+
1/18 H // Ms^+

1/9 Ms^+ // a
1/9 A^+ // a
1/9 H // a

1/9 Ms^+ // H^+
1/9 A^+ // H^+
1/9 H // H^+

(my punnet square was a total of 36, so i have halved it down, so the 1/9 means 4 out of 36 )

so am i on the right lines here? or have i done too much/ too less?

Oh, my. Way off track.

You have made the commonest newbie mistake -- trying to pair genes that cannot be paired. You cannot pair an albino (a) gene with anything except another a mutant gene or an a^+ gene. A Mack snow mutant gene (Ms) can only be paired with another Ms mutant gene or an Ms^+ gene, and a hypo mutant gene (H) can only be paired with another H mutant gene or an H^+ gene. Trying to make a pair of genes from an a gene and an Ms^+ gene is like trying to pair an earring with a rubber boot.

The male is Ms//Ms^+ a//a H^+//H^+. Each sperm gets one gene from each pair of genes. So the sperm get either an Ms or an Ms^+ gene. All the sperm get an a mutant gene because both genes in the pair are a. And all the sperm get an H^+ gene because both genes in the pair are H^+.

Sperm genotypes:
1/2 Ms a H^+
1/2 Ms^+ a H^+

Female = Ms^+//Ms^+ a^+//a^+ H//H
Each egg gets one gene from each pair of genes. The two genes in each gene pair are the same. So every egg gets an Ms^+ gene, an a^+ gene and an H gene.

Egg genotype:
Ms^+ a^+ H

Plug that into a Punnett square that is 1 X 2 boxes.

And the result is
1/2 Ms//Ms^+ a^+//a H//H^+ = Mack snow hypo (het albino)
1/2 Ms^+//Ms^+ a^+//a H//H^+ = hypo (het albino)