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anery's recessive
hypo is co-dominant anery x hypo will give 1/2 hypo het anery, 1/2 normal het anery to get ghost the hypo needs to carry the anery gene as well ie: hypo het anery x anery or ghost x anery or ghost x ghost or hypo get anery x het anery etc etc snow is the result of anery + albino anery x albino = normals dh snow sometimes hypo het anery is called hypo dh ghost ghost != snow
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5this is where it helps to ignore the silly fancy breeder labels and think about the morph in terms of what genes are at play.
Ignore double hets, fancy names etc just understand what goes on in the background. Using ghost as an example you'd know that ghost is visual hypo visual anery in the same snake. So you'd know that both parents have to carry the anery gene (either visually or as a het) and only one or both have to be hypo. Snow = visual anery and visual albino in the same snake so again, knowing that both albino and anery are simple recessive you can work out that both parents have to have both genes either visually or as a het. It's much harder to get confused if you ignore the silly breeder labels and work it out.
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--- Mason 1.0 of "Quixotic_Axotlotl" ![]() http://masonexotics.co.uk/ourcollection.aspx Locality Boas and Retics A Passion. |
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Quote:
Using ghost as an example, there are two anerythristic mutant genes. And there are either two salmon (AKA hypo) mutant genes (rare) or one salmon mutant gene paired with a normal gene (the usual situation). Using snow as an example, there are two anerythristic mutant genes and two albino mutant genes. |
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