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Quote:
![]() Mack Ghost X Mack Ghost (in descending order of likelihood) = 25.0% Mack Ghosts 12.5% Super Snow Ghosts 12.5% Mack Super Hypo Ghosts 12.5% Mack Snows not hypo 12.5% Normal Hypos 6.25% Super Snow Super Hypo Ghosts 6.25% Super Snow not hypo 6.25% Normal Super Hypos 6.25% Normal, not snow or hypo
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- Ssthisto ![]() ![]() We HAD a three-bedroom house... Current lodgers: 1.0 E. c. maurus, 0.1 P. regius |
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Awww, it's not that bad....
Mack Ghost is sort of: MmHh Where M is the incomplete dominant Mack, m is normal "not mack", H is the incomplete dominant hypo, h is normal "not hypo". (You can see that, if Mack or Hypo was a recessive, you'd call this "het mack, het hypo" ... but because they're at least partially dominant genes, you can SEE the hets, and it's the "super" form that's homozygous) So if you cross a MmHh to another MmHh you can get: Mack Ghosts (MmHh) Super Snow Ghosts (MMHh) Mack Super Hypo Ghosts (MmHH) Mack Snows not hypo (Mmhh) Normal Hypos (mmHh) Super Snow Super Hypo Ghosts (MMHH) Super Snow not hypo (MMhh) Normal Super Hypos (mmHH) Normal, not snow or hypo (mmhh) The percentages are just the probability of each combination happening ![]()
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- Ssthisto ![]() ![]() We HAD a three-bedroom house... Current lodgers: 1.0 E. c. maurus, 0.1 P. regius |
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The fastest way would be to breed a Super Snow to a Super Hypo. That way, you get 100% Hypo Macks (AKA "Mack Ghost"). Each parent HAS to give a copy of their mutant gene to the offspring, because they don't have anything else to give.
You could try Mack to Super Hypo, too, for 50% odds.
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- Ssthisto ![]() ![]() We HAD a three-bedroom house... Current lodgers: 1.0 E. c. maurus, 0.1 P. regius |
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LOL knew it didn't look right. Was having a brain fart
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