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Old 19-09-2007, 08:27 PM
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Default What are the Parents?

Hi

I have taken in 12 Hatchling corns from same batch and would like to know what the parents would be, in the batch are:

Snow Stripe
Amel Stripe
Amel Cubed
Amel Motley
Classic Motley
Amels
and Classics

Could anyone tell me.
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Old 19-09-2007, 08:30 PM
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i'd guess at amel, het anery, het motley x amel het anery, het stripe
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Old 19-09-2007, 08:40 PM
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Cheers Capt. What of them in your opinion would be best bred together from the batch?
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Old 19-09-2007, 08:48 PM
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snow stripes for definite if more than one pair, amel stripes too
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Old 19-09-2007, 08:56 PM
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Thanks mate.
I have a pair of 06 Amel Stripes also so will keep all striped corns as they are my faves.
There are poss a couple of RO's in the batch too as don't look like standard Amels.
Bit of a mixed bag!
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Old 19-09-2007, 09:03 PM
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Quote:
Originally Posted by captaincaveman View Post
i'd guess at amel, het anery, het motley x amel het anery, het stripe
theres a flaw in your guestimate.... theres normal hatchlings which isn't possible from homo amel x homo amel

maybe normal het snow motley x amel het anery stripe?
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Old 19-09-2007, 09:06 PM
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So what offspring would there be from a Snow Stripe x Anery Stripe, saying snow stripe is from above parentage??
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Old 19-09-2007, 09:10 PM
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Quote:
Originally Posted by wrecexotics View Post
So what offspring would there be from a Snow Stripe x Anery Stripe, saying snow stripe is from above parentage??
100% anery stripe het amel
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Old 19-09-2007, 09:13 PM
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Excellent, thanks for that eeji
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Old 19-09-2007, 11:22 PM
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Quote:
Originally Posted by wrecexotics View Post
Hi

I have taken in 12 Hatchling corns from same batch and would like to know what the parents would be, in the batch are:

Snow Stripe
Amel Stripe
Amel Cubed
Amel Motley
Classic Motley
Amels
and Classics

Could anyone tell me.
My first post. Interesting forum here.

To get both amelanistic and nonamelanistic babies, at least one parent must have a normal gene at that gene locus. In other words, both parents must be heterozygous amelanistic or one parent is amelanistic and the other is heterozygous amelanistic. From the number of amelanistics in the list, I think the second choice is the more likely.

Anerythristic is one of the components of snow. To get both anerythristic babies and nonanerythristic babies, both parents must be heterozygous anerythristic or one parent is anerythristic and the other is heterozygous anerythristic . From the number of anerythristics (snows) in the list, I think the first choice is the more likely.

Striped and motley are members of a multiple allele series, which makes the parentage the toughest to figure out. There is also the question of how accurately the striped babies are identified.

All I can say at the moment for certain is that one parent had a normal gene at the motley locus. If the striped babies have two striped mutant genes, then one parent had a gene pair containing a normal gene and a striped mutant gene (normal//striped). And the other parent had a gene pair containing a motley mutant gene and a striped mutant gene (motley//striped).

If the striped babies actually have a motley//striped gene pair instead of striped//striped gene pair, then the parents could be

motley//motley x normal//striped
striped//striped x normal//motley
motley//striped x normal//motley
motley//striped x normal//striped
normal//motley x normal//striped
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